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Enthalpy of formation of ammonia is - '4...

Enthalpy of formation of ammonia is - '46.0 kJ mol^(-1)'.
The enthalpy change for the reaction:
'2 NH_3(g) rarr N_2(g)+3 H_2(g)'

A

46.0 kJ mol^(-1)'

B

-23.0 kJ mol^(-1)'

C

+92.0 kJ mo l^(-1)'

D

-92.0 kJ mol^(-1)'

Text Solution

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The correct Answer is:
C
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