Ethyl acetate is formed by the reaction between ethanol and acetic acid and equilibrium is represented as:
'CH_3 COOH_( )+C_2 H_5 OH_(l) hArr CH_3 COOC_2 H_5_(l)+H_2 O_(l)'
i) Write the concentration ratio (reaction quotient), 'Q_c', for this reaction (note: water is not in excess and is not a solvent in this reaction)
ii) At '293 K', if one starts with '1.00' mol of acetic acid and '0.18 mol' of ethanol, there is '0.171' mol of ethyl acetate in the final equilibrium mixture. Calculate the equilibrium constant.
iii) Starting with '0.5' mol of ethanol and '1.0' mol of acetic acid and maintaining it at 293 ' K, '0.214' mol of ethyl acetate is found after sometime. Has equilibrium been reached?