Whenever a reaction between an oxidizing agent and a reducing agent is carried out, a compound of lower oxidation state is formed if the reducing.agent is in excess and a compound of higher oxidation state is formed if the oxidising agent is in excess. Justify this statement giving three illustrations.

Explain oxidation, reduction, oxidising agent and reducing agent ?

If an element is in its highest possibel oxidation state in a compound, it can act as an oxidising agent. If an element is in its lowest possible oxidation state in a compound, if can act as reducing agent. If an element is in the intermediate oxidation state in a compound, it can serve as both oxidising and reducing agent. Based on the above three guidelines, classify the following compounds into three categories and post them in the table given below. KMnO_4 , H_2O_2 , H_2C_2O_4 , FeSO_4 , HCIO_4 , SO_2 , Na_2S_2O_3 , K_2Cr_2O_7

Analyse oxidation numbers in the given equation and list the oxidising agent and reducing agent in the tabel given below.

From the given chemical equation identify the oxidising agent and the reducing agent by writing the chemical equation of oxidation and reduction Mg + F_2 rarr MgF_2

Which element in 3d-series is a strong reducing agent in its +2 oxidation state ? Ti V Cr Mn

From the given chemical equation identify the oxidising agent and the reducing agent by writing the chemical equation of oxidation and reduction 2Na +Cl_2 rarr 2NaCl

Write the chemcial formula of compound formed by the combination of X and Y and label the oxidation states?