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In the reaction: 3 CuO+2 NH3 rarr N2+3 ...

In the reaction:
`3 CuO+2 NH_3 rarr N_2+3 H_2 O+3 Cu`
the change of `N H_3` to `N_2` involve : Loss of 6 electrons per mol of `N_2`, Loss of 3 electrons per mol, of `N_2`, Gain of 6 electrons per mol of `N_2` , Gain of 3 electrons per mol.of `N_2`

A

Loss of 6 electrons per mol of 'N_2'

B

Loss of 3 electrons per mol, of 'N_2'

C

Gain of 6 electrons per mol of 'N_text , '

D

Gain of 3 electrons per mol.of 'N_2'

Text Solution

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The correct Answer is:
A
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