The molar conductivity of `0.025 mol L^(-1)` methanoic acid (HCOOH) is `46.1 Scm^2 mol^(-1)`. Calculate its degree of dissociation and dissociation constant. Given `lambda^@ (H^+)=349.6 S cm^2 mol^-1` and `lambda (HCOO^-)= 54.6 S cm^2 mol^-1`

Explanation

"ethanoic acid is `46.1 Scm^2 ~mol^-4 .` Calculate its degree of dissociation and dissociation constant. Given `lambda^0(H^*)=349.6 Scm^2 ~mol^-1` and `lambda^0`
`(HCOO^-)=54.6 Scm^2 ~mol^-1`