If a current of 0.5 ampere flows through a metallic wire for two hours, then how many electrons flow through the wire?

Explanation

Ans: Q=I xx t=0.5 xx 2 xx 60 xx 60=3600 C
Charge present ọn electron =1.6029 xx 10^-19 C
therefore No òf electrons flowing
3600/1.6029 xx 10^-19=36 xx 10^2:/1.6029 xx 10^-19=22.45 xx 10^11=2.25 xx 10^12
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