The resistance of a conductivity cell containing `0.001 M^circ KCl` solution at `298 ~K` is `1500 Omega`. What is the cell constant if conductivity.of `0.001 M` KCl solution at `298 K` is `0.146 xx 10^-3` `S cm^-1`

Explanation

Ans: Cell constant = Conductivity: xx Resistance
=0.146 xx 10^-3 Sem^-1 xx 1500 Omega=0.219 ~cm^-1
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