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Calculate the single electrode potential...

Calculate the single electrode potential at 298 K of the `Cu ^2 +` / Cu electrode in which the concentration of ions is 2.0M

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According to Nernst equation. `` E=E^prime prime +0.0591/2 log [Cu^2+]=0.34+0.0591/2 cdot log 2 =0.34+0.0295 .5 xx log 2=0.3489 ~V endaligned ``
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