Copper sulphate solution `(250 mL)` was electrolysed using a platinum anode and a copper cathode. A constant current of `2 mA` was passed for 16 minutes. It was found that after electrolysis, the absorbance of the solution was reduced to `50 %` of its original value. Calculate the concentration of copper sulphate in the solution to begin with.

Explanation

Ans: Number of equivalents of `Cu^3 *` lost during
``

electrolysis = 1 xx t xx 1/96500 C=2 xx 10^-3 ~A xx 16 xx 60 ~s/96500
=1.989 xx 10^-5
endaligned
``
: Number of moles of `Cu^2+` lost during electrolysis
...