The conductivity of `0.001028 mol L^-1` acetic acid is `4.95 xx 10^-5 Scm^-1`, Calcụlate its dissociation constint if `Lambda_m^0` for acetic acid is `390.5 Scm^2 mol` :

Explanation

Lambda_m^c=r xx 1000/C =4.95 xx 10^-5 xx 1000/0.001028
=48.15 Scm^2 ~mol^-1 .
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alpha=Lambda^C m/Lambda^0 m=48.15 S^2 m^2 m o l^-1/390.5 cdot S c m^2 m o l^prime=0.1233
because quad K=C alpha^2/1-alpha cdot
=.001028 xx(0.1233)^2/1-0.1233^*=1.78 xx 10^-5 moll^-1
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