Caleulate `Lambda_m^0` for acetic acid. Given that `Lambda_m^0(HCl)=426 ohm^-1 ~cm^3 ~mol^-1 , Lambda_m^0(NaCl)= 126 ohm^-1 ~cm^2 ~mol^-1` and `Lambda_m^0(CH_3 COONa)=91 ohm ^-1 ~cm^2 ~mol^-1`

From the following molar conductivities at infinite dilution lamda_(m)^(@) for Ba(OH)_(2)=457.6ohm^(-1)cm^(2)mol^(-1) lamda_(m)^(@) for BaCl_(2)=240.6ohm^(-1)cm^(2)mol^(-1) lamda_(m)^(@) for NH_(4)Cl=129.8ohm^(-1)cm^(2)mol^(-1) Calculate lamda_(m)^(@) for NH_(4)OH

At 298 K, the conductivity of a saturated solutioni of Agcl in water is 2.6xx10^(-6)ohm^(-1)cm^(-1) givem lamda_(m)^(oo)(Ag^(+))=63ohm^(-1)cm^(2)mol^(-1) and lamda_(m)^(oo)(Cl^(-))=67ohm^(-1)cm^(2)mol^(-1) The solubility product of AgCl is

The conductivity of a saturated solution of a springly soluble salt, MX_(2) is found to be 4.0xx 10^(-6) Omega^(-1) cm^(-1) . If lamda_(m)^(oo) ((1)/(2) M^(2+)) = 50.0Omega^(-1) cm^(2) mol^(-1) and lamda_(m)^(oo) (X^(-)) = 50 Omega^(-1) cm^(2) mol^(-1) , the solubility product of the salt is about

The specific conductivity of the saturated aqueous solution of AgCl is 1.82xx10^(-6) ohm^(-1) cm^(-1) at 298K. Calculate me solubility of AgCl. [wedge_(m)^(@)(Ag^(+))=61.83 ohm^(-1) cm^(2) mol^(-1)] and wedge_(m)^(@) (CI)^(-)=76.41 ohm^(-1) cm^(2) mol^(-1)

The molar conductivity of 0.025 mol L^(-1) methanoic acid (HCOOH) is 46.1 Scm^2 mol^(-1) . Calculate its degree of dissociation and dissociation constant. Given lambda^@ (H^+)=349.6 S cm^2 mol^-1 and lambda (HCOO^-)= 54.6 S cm^2 mol^-1

Kohlrausch’s law Is useful for determining lambda_m^0 of weak electrolytes.The molar conductance of 0.3 M acetic acid Is 176.6 ohm^(-1) cm^2 mol^-1 . Calculate its degree of dissociation if molar conductance at infinite dilution is 384 ohm^-1 cm^2 mol^-1 .

The limiting molar conductivities Lambda_m^- for NaCl, KBr and KCl are 126,152 and 150 ~cm^2 mol^-1 respectively. The Lambda_s ,for Na Br is

Kohlrausch's law helps to determine the degree of dissociation of a weak electrolyte at a given concentration. The molar conductivity Lambda_m of .001M acetic acid is 4.95xx10^(_5)Scm^2mol^(-1) .Calculate the degree of dissociation (alpha) at this concentration if limiting molar conductivity lamda_m^0 for H+is 340xx10^(-5)Scm^2mol^(-1) and CH_3COO^- 50.5xx10^(-5)Scm^2mol^(-1)