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The passage of current liberates H2, at ...

The passage of current liberates `H_2`, at cathode and `Cl_2` at anode. The solution is : Copper chloride in `H_2 O`, NaCl in `H_2 O`, `H_2 SO_4`, water

A

Copper chloride in H_2 O

B

NaCl in H_2 O

C

H_2 SO_4

D

water

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The correct Answer is:
B
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