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During the electrolysis of NaCl, when pl...

During the electrolysis of `NaCl`, when platinum electrode is taken, `H_2`, is liberated at the cathode while-it form sodium amalgam with mercury cathode. This is because

A

Hg is more inert than Pt

B

More voltage is required to reduce `H^+ at Hg` than at `Pt`

C

Na is dissolved in `Hg` while it does not dissolve in `Pt`.

D

Con. of `H^+` ions is larger when `Pt` electrode is taken'

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The correct Answer is:
B
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