The activation energy for the reaction,`2HI(g)toH_2(g)+I_2(g)`is `209.5kj mol^(-1)`at 581 K.Calculate the fraction of molecules of reactant having energy equal to or greater than activation energy.

Explanation

tion of molecules with energy equal to greater than activation energy. `x=(e)^(-(F)`
Hence `log x=(( Ea ))(2.303 R T)`
`log x=-(209500)(2.303 * 8.314 * 581)=-18.8323`
`=19,1677 , (X)=antilog 19,1677= 1.47*10^-19