For the reaction: 2A+B→A 2 B, the rate =k[A[B]2 with k=2.0×10^−6mol^−2L ^2 s^−1. Calculate the initial rate of the reaction when [A]=0.1molL −1 ,[B]=0.2 molL −1 . Calculate the rate of reaction after [A] is reduced to 0.06 molL −1

Explanation

Initial rate ` = (k)[(A)][(B)]^(2)`,
`(k) =2.0 *10^(-6) (mol)^(-2) (L)^(2) (s)^(-1)`
Initia l Rate =`2.0 * 10^(-6) *(0.1) * (0.2)^(2)`
=.008 * 10^(-6)=8 * 10^(-9) (mol) (L)(s)^(-1)`
When `[(A)]` is reduced from `0.1 (mol) (L)^(-1)` to `0.06 (mol) (L)^(-1)`
i.e. `(0.1-0.06)=0.04 (mol) (L)^(-1)` has reacted