Calculate the half-life of a first order reaction from their rate constants given below: i) `200 (s)^(-1)`

Explanation

i) `Rate constant =200 (s)^(-1)`
For a first order reaction, `t_(1/2)=(0.693)(k)=(0.693)(200)`
`t_(1 / 2)=3.47 xx 10^(3)` seconds.
ii) Rate constant `=2 min^-1, t_(1 / 2)=(0.693)(k)=(0.693)(2) =0.35 (min)`
iii) Rate constant =`4 years^(-1)`
`(t)_(1 / 2)=(0.693)(k)=(0.693)(4)=0.173` years.