The rate constant for a first order reaction is 60 (s)^(-1) .How much time will it take to reduce the initial concentration of the reactant to its `1 / 16th value?

Explanation

`k=(2.303)(t) log (a)(a-x) a-x=(1)(16) a`
`t=(2.303)(k) log (a)(a-x) k=60 (s)^(-1)`
`=(2.303)(60) log (a)(1 / 16^(a))=(2.303)(60) log 16`
=0.046 (s)