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The decomposition of hydrocarbon follows...

The decomposition of hydrocarbon follows the equation`k=(4.5xx10^11s^-1) e^-28000K/t`
Calculate `E_(a)^(*)`

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` log (k)=log(A)-((Ea)(2.303 (RT)` The decomposition of the hydrocarbon follows the equation `k=4.5 * 10^(11) (s)^(-1) (e)^(-28000K/T` Applying logs. `log k=log 4.5 * 10^(11)-(28000)(J) (K)` Comparing it with equation no (i) `(Ea)(2.303 R)=(28000)(2.303)` `(Ea)=28000 * 8.314 (J) =28 * 8.314 (kJmol)^(-1) (s)_(1) =232.79 (k)(J) (mol)^(-1)`
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