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In a reversible reaction 2NO{2}harrN{2}O...

In a reversible reaction `2NO_{2}harrN_{2}O_{4}` the rate of disapperance of `NO_{2}` is equal to : `((2 (k)_{1}/(k)_(2)) [(NO)_(2)] ^(2)` , `2K_{1}[NO_{2}]^2-2k_{2}[N_{2}O_{4}]` `2k_{1}[NO_{2}]^2-k_{2}[N_{2}O_{4}]` , `(2K_{1}-k_{2})(NO_{2})`

A

`(2 (k)_{1}(k)_(2)[(NO)_(2)right]^(2)`

B

`2K_{1}[NO_{2}]^2-2k_{2}[N_{2}O_{4}]`

C

`2k_{1}[NO_{2}]^2-k_{2}[N_{2}O_{4}]`

D

`(2K_{1}-k_{2})(NO_{2})`

Text Solution

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The correct Answer is:
B
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