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The rate law for a reaction between the ...

The rate law for a reaction between the substances `(A)` and `(B)` is given by, rate =k `[mathbf(A)]^(n)[(~B)]^((m))` On doubling the concentration of `(A)` and halving the concentration of B, the ratio of the new rate to the earlier rate of the reaction will be

A

m+n

B

n-m

C

`2^(n)-(m)`

D

`2 ^ 1 /m+n

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The correct Answer is:
C
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