Why is the reduction of a' metal'oxide easier if the metal formed is in liquid state at the temperature of reduction?

Explanation

The reduction of a metal oxide can be repre-
The entropy of the liquid is more than the entropy of the metal in the solid state. .Delta S. will be more .+. ve
when the metal formed is in liqüid state. Hence .triangle G. .=Delta H-I Delta S., tend to be more negative. Hence the reaction.becomes more probable or easier.