The `E_((m^(2+)//m))^0` values for copper is positive (0.34 V). What is the reason for this?

Explanation

The E^(circ). for .C (C)^(2+) / C_(1) is +0.34. Electrode potential values depend upon factors sucl as (i) energy of sublimation-of the metal, (ii) the ionisation energy and (jii) hydration energy. The high energy required to transform Cu(s) to .(Cu)^(J)+)(a) hat(g) is not balanced by
the low value of its hydration energy. Hence it shows n positive value of its reduction potential.