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Transition elements show various oxidati...

Transition elements show various oxidation -states and many, of the transition metal ions are attracted by a magnetic field. a. Give reason for variability of oxidation state. b. Name the two types of magnetic behaviour. c. The observed magnetic moment of `Sc^(3+)` was found to be 'zero '.Calculate the magnetic moment of `Sc^ (3+)`, using the 'spin-only' formula and compare the result of observed and calculated magnetic moment.

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a. They show a variety of oxidation states in their compounds due to the availability of both .(ns). and .(n) dot 1). d electrons for-bund formation: Their general oxidation-state is .+2. and other oxidation states like .+1,+3,+4,+5. .+6. and .+7. are also.possible. b. Paramagnetism and diamagnetism. c. .operator name(Sc)(Z=21)=[(Ar)] 4 s^(2) 3 (~d)^(t) (Sc)^(3+)=4 (~s)^(circ) 3 (~d)^(circ). Magnetic .moment, .mu=sqrt(n(n+2). where .n .^(+). is the number of umpaited elecu trons .therefore mu. of .(Sc)^(2)=sqrt(0(0+2)=0. Both the observed and calculated magnetic moment of .dot (Se)^(l+). is zero.
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Presence of unpaired electrons makes a species paramagnetic. Each unpaired electron has a magnetic moment associated with its spin angular momentum and orbital angular momentum. For the compounds of the first series of transition metals, the contribution of the orbital angular momentum is effectively quenched and hence is considerably important. For these, the magnetic moment is determined by the number of unpaired electrons and is calculated by using the spin-only formula, i.e., mu = sqrt(n(n+2)) where n=number of unpaired electrons and mu =magnetic momentin (in Bohr magneton, B.M.). If n=1, then mu = 1.73 B.M . Which one of the following transition metal ions is paramagnetic?

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