Home
Class 12
CHEMISTRY
Explain why the E^(0) value for the (Mn)...

Explain why the `E^(0)` value for the `(Mn)^(3+) / (Mn)^(2+)` couple is much more positive than thát for `(Cr^(3+))/(Cr^(2+)) or (Fe^(3+))/(Fe^(2+))`

Text Solution

Verified by Experts

Because .(Mn)^(3+)(3 (~d)^(+). has strong tendency to accept an, .e^(-). to undergo reduction. to racquire .3 (~d)^(5). configuration. forming .(Mn)^(2+). .(Mn)^(3 *)+(e)^(-) rarr (M) (n)^(2+). .[(Ar)] 3 (~d)^(4). .[(Ar)] 3 (~d)^(5). Hence the reduction potential of .(Mn)^(4) / (Mn)^(2+). is much more positive:
Promotional Banner

Topper's Solved these Questions

  • SURFACE CHEMISTRY

    V PUBLICATION|Exercise QUESTION BANK|126 Videos
  • The p-BLOCK ELEMENTS

    V PUBLICATION|Exercise QUESTION BANK|147 Videos

Similar Questions

Explore conceptually related problems

Assertion : In aqueous solution Cr^(+3) is more stable than Fe^(+3) Reason : E_(Cr^(+3))^(0)//Cr^(+2)=-0.41V , but E_(Fe^(3+)//Fe^(2+))^(0)=0.77V

Why are Mn^(2+) compounds more stable than Fe^(2+) towards oxidation to +3 state?

Why are Mn '2+)' compounds more stąble than Fe towards oxidation to their +3 state?

At equimolar concentration of Fe^(2+) and Fe^(3+) what must [Ag^(+)] be so that the voltage of the galvanic cell made from Ag^(+)//Ag and Fe^(3+)//Fe^(2+) electrodes equals zero? The reaction is Fe^(2+) + Ag^(+) hArr Fe^(3+) + Ag . Determine the equilibrium constant at 25^(@)C for the reaction. Given E_(Ag^(+)//Ag)^(@)= 0.799V and E_(Fe//Fe^(2+))^(@)= 0.771V

Fill in the blanks: Fe^(2+) rarr Fe^(3+) + ………….. (III) …………

Calculate the cell potential for the following galvanic cell: The first electrode consists of Fe^(3+)|Fe^(2+) complete in which [Fe^(3+)]=1M and [Fe^(2+)]=[0.1M] The second electrode consists of MnO_4(-)|Mn^(2+) couple in acidic solution in which [MnO_4^-]=1times 10^-2 M, [Mn^(2+)]=1 times 10^-4 M and [H^+]=1 times 10^-3 M [E_(Fe^(3+),Fe^(2+))^@=0.771V, E_(MnO_4^-, Mn^(2+))^@=1.51V)

Write the Nernst equation for the reaction? i) 2Cr(s)+3Cd^(2 +)(aq)to2Cr^(3+)(aq)+3Cd(s) ii) 2Cr+3Fe^(2 +)to2Cr^(3+)+3Fe