`[Co(NH_3)_6]^3+` is an inner orbital complex whereas `[Ni(NH_3)_6]^(2+)` is an outer orbital complex.Explain.

Explanation

In .[Co(NH_3)_6]^3, C o. is in .+3. oxidation state and has .d^prime. conifiguration. In presence of .NH_y., the .3 d. electrons pair up leaving two-d-orbitals empty to be involved in hybridization. The hybridization is .d^2 s p^3. forming .inner.orbital complex. In .[Ni(NH_3)_c]^2+, Ni. is in .+2. oxidation state and has .d^8..configuration.
For octahedral conifiguration, the hybridization.in:
volved is .s p^3 d^3.. forming outer orbital complex.