Explain why chlorination of n-butane in presence of light at 298 K gives a mixture of 72 % 2-chlorobutane and 28 % of 1- chlorobutane.

The product formed on reaction of n-butanol with SOCl_(2) in presence of pyridine is : chlorobutanol, 1-chlorobutane, chlorobutanone, 2-chlorobutane

Statement 1 :Chlorination of ethyl benzene with Cl_2 in presence of heat and light mainly yields 1-chloro-2- phenylethane. Statement 2 : The reaction occurs through intermediate formation of the radical, C_6H_5CHCH_3

Find true and false statements among the followingand make corrections to the wrong statements. a. Chlorobenzene on further chlorination produces ' m' -dichlorobenzene b. 2 - Chlorobutane on reaction with alcoholic KOH produces 1 -butene. c. 1,1-Dichloroethane on treatment with aq.NaOH produces acetaldehyde. d. Trichloroacetaledehyde is also called chloritonte:

The time required for 10 % completion of a first order reaction at 298 (K) is equal to that required for its 25 % completion at 308 K . If the value of A is 4xx10^10 (s)^(-1) . Calculate (k) at 318(K) and (Ea) .

Reaction of propene with dibrorane followed by alkaline hydrolysis in fhe presence of hydrogen peroxides gives 1 - propanol 2 - propanol 1,2 -dihydroxypropane n-propane

How will you bring about the following conversions? i. Ethanol to but-1-yne ii. Ethane to bromo:ethene iii. Propene to 1 -nitropropane iv. Toluene to. benzyl alcohol v. Propene to propyne vi. Ethanol to ethyl fluoride vii. Bromomethane to propanone viii. But-1-ene to but -2-ene ix. 1 chlorobutane to n- octane x. Benzene to biphenyl.