A hollow charged conductor has a tiny hole cut into its surface. Show that the electric field in the hole is `( sigma //2 epsilon_(0)) hat n` , where `hatn` is the unit vector in the outward normal direction, and `sigma` is the surface charge density near the hole.

The magnitude of the electric field on the surface of a sphere of redius r having a uniform surface charge density sigma is

A spherical charged conductor has sigma as the surface charge density. The electricfield on its surface is E. The radius of the sphere is doubled keeping the surface charge density unchanged. Then the electric field on the surface of the new sphere is,

Careful measurement of the electric field at the surface of a black box Indicates that the net outward flux through the surface of the box is 8.0 xx 10^3Nm^2C : What is the net charge Inside the box?

A uniformly charged conducting spheres of 2.4m diameter has a surface charge density of 80.0mu Cm^-2 ?.What is the total electric flux leaving the surface of the sphere?

A spherical conductor of radius 12cm has a charge of 1.6x10^(-7) C distributed uniformly on its surface. What is the electric field a) Inside the sphere. b) Just outside the sphere. c) At point 18cm from the centre of the sphere?

Two charged conducting spheres of radii a and b are connected to each other by a wire. What is the ratio of electric fields at the surfaces of the two spheres? Use the result obtained to explain why charge density on the sharp and pointed ends of a conductor is higher than on its flatten portions.