Obtain the formula for the electric field due to a long thin wire of uniform linear charge density E without using Gauss’s law. [Hint: Use Coulomb’s law directly and evaluate the necessary integral.]

Using this law, derive an expression for electric field due to thin uniformly charged shell.

Apply Gauss's law to find the electric field due to an infinitely long plane sheet of charge.

Electric field lines are a pictorial represe-ntation of the electric field around charg-es:- State Gauss’s Law in Electrostatics.

One can determine the direction of electric field around a stationary charge with the help of electric field lines. Br Consider a spherical shell of radius .R. is uni formly charged with charge .+q.. By using Gauss.s theorem, find the electric field intensity at a point .p.. br i) Outside the spherical shell. br ii) Inside this spherical shell

Two charged conducting spheres of radii a and b are connected to each other by a wire. What is the ratio of electric fields at the surfaces of the two spheres? Use the result obtained to explain why charge density on the sharp and pointed ends of a conductor is higher than on its flatten portions.

In symmetric charge configurations, the electric field can be easily calculated using Gauss’s law. A sphere of radius ‘a‘ is made of Insulating material and has charge distributed uniformly throughout its volume. Let the charge density be rho . Find the field due to the charge for rlea .

The idea of Electric field lines. is useful in pictorially mapping the electric field around charges. Br State Gauss.s theorem in electrostatics.

Gauss.s law is true for any closed surface, no mat ter what its shape or size say the following state ments are true or false. a) Gauss.s law implies that the total electric flux through a closed surface is zero if no charge is enclosed by the surface. b) This law is useful for the calculation of electro static field when the system doesn.t possess any symmetry