A spherical Gaussian surface encloses a charge of `8.85 xx 10^(-8),C`. (i) Calculate the electric flux passing through the surface (ii) If the radius of the Gaussian surface is doubled, how would the flux change?

The flux of electricfield passing through the curved surface of the hemisphere of radius R, if vec(E) is radial to the sphere as shown :

A point charge causes an electric flux of -1.0 xx 10^3 Nm^2//C to pass through a spherical Gaussian surface of 10.0 cm radius centered on the charge:- If the radius of the Gaussian surface were doubled, how much flux would pass through the surface?

A point charge causes an electric flux of -1.0xx10^3Nm^2//C to pass through a spherical Gaussian surface of 10.0 cm radius centred on the charge. If the radius of the Gaussian surface were double, how much flux would pass through the surface ?

A closed surface encloses an elec-tric dipole. What is the electric flux through the surface ?

Name the theorem used to find the electric flux through a surface enclosing charge.

A spherical charged conductor has sigma as the surface charge density. The electricfield on its surface is E. The radius of the sphere is doubled keeping the surface charge density unchanged. Then the electric field on the surface of the new sphere is,

The total electric flux through a closed surface is zero if no charge is enclosed by the surface. Check whether this statement is true or false?

Gauss.s law is true for any closed surface, no mat ter what its shape or size say the following state ments are true or false. a) Gauss.s law implies that the total electric flux through a closed surface is zero if no charge is enclosed by the surface. b) This law is useful for the calculation of electro static field when the system doesn.t possess any symmetry

A point charge causes an electric flux of -1.0xx10^3Nm^2//C to pass through a spherical Gaussian surface of 10.0 cm radius centred on the charge .What is the value of the point charge?