Show that the force on each plate of a parallel plate capacitor has a magnitude equal to (1/2)QE, where Q is the charge on the capacitor and E is the magnitude of electric field between the plates. Explain the origin of the factor (1/2).

If the dielectric slab is absent and the capacitor is charged to a surface charge density o, the electric field in between the plates is

What is the area of the plates of a 0.1 µF parallel plate air capacitor, given that the separation between the plates is 0.1 mm.

A parallel plate capacitor consists of two metallic plates separated by a small distance with a dielectric in between : A parallel plate air capacitor has charge densities + sigma and - sigma on the plates. Write the expres sion for electric field between the plates. What happens to the field if the separation between the plates is doubled?

The Capacity of a parallel plate capacitor be comes 10 muF when air between the plates is re placed by a dielectric slab (k =2). What is the capacity of the capacitor with air in between the plates?