Obtain the binding energy (in MeV) of a nitrogen nucleus `(""_(7)^(14)N)` , given `m(""_(7)^(14)N)`
`=14.00307" "u`

Obtain the binding energy of a nitrogen nucleus 14_7 N. Given m ^14_7 N = 14.00307 u.

The number of neutrons in the parent nucleus which gives ""_(7)^(14)N on beta -emission is

Find the binding energy per nucleon of (Ca^40_20) nucleus given m^40(_20) Ca = 39.962589u , m_p = 1.00783u , m_n=1.00876u , TAKE 1amu = 931MeV/C^2

The energy released in the fission reaction ""U^(236) to ""X^(117) + Y^(117) + 2 ""_(0)n^(1) , given that the binding energy per nucleon of X and Y is 8.5 MeV and that of ""_(92)U^(236) is 7.6 MeV, is nearly.

The kinetic energy for 14g of N_(2) gas at 127^(@)C is nearly