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In triangle /\ABC, AD is the median from...

In triangle `/_\ABC`, AD is the median from A.`/_\BAD`=`35^circ`, AB=18 cm and AD= 12 cm. Find:
a) The ratio of the areas of the triangles `/_\ADC` and `/_\ABC`.
b) The perpendicular distance from D to AB.
c) The length of BC. [sin `35^circ`=0.57, cos `35^circ`=0.82, tan `35^circ`=0.7]

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