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Find the set of the equation x^2 +x -2= ...

Find the set of the equation `x^2 +x -2= 0` in roster form.

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The given equation can be writtern as (x-1)(x_2) = 0 i.e., x = 1 ,-2. Therefore, the solution set of the givẻn equation .can be written.in roster form as .{1,-2}.
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Knowledge Check

  • If the roots of the equation x^(2) + px + c =0 are 2,-2 and the roots of the equation x^(2) + bx + q=0 are -1,-2 , then the roots of the equation x^(2) + bx + c =0 are

    A
    `-3,-2`
    B
    `-3,2`
    C
    `1,-4`
    D
    `-5,1`

  • Roots of the equation x^(4)-2x^(2)+4=0 forms a

    A
    A) rectangle
    B
    B) square
    C
    C) rhombus
    D
    D) parallelogram

  • Sum of the roots of the equation |x-3|^(2)+|x-3|-2=0 is

    A
    2
    B
    4
    C
    6
    D
    16

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