Find the radius of the circle in which a central angle of `60^(circ)` intercepts an arc of length `37.4 cm` (use `pi=(22)/(7))`

Explanation

Here .l=37.4 cm. and .theta=60^(circ)=(60 pi)/(180). radian .=(pi)/(3). .

Hence, by .(r)=(l)/(theta)., we have .

r=(37.4 xx 3)/(pi)=(37.4 xx 3 xx 7)/(22)=35.7 cm