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Show tht tan (x-y)=(tan x-tan y)/(1+tan ...

Show tht `tan (x-y)=(tan x-tan y)/(1+tan x tan y)`

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If we replace by .-(y). in Identity 10, we get
`tan (x-y)=tan [x+(-y)]=(tan x+tan (-y))/(1-tan x tan (-y))=(tan x-tan y)/(1+tan x tan y)`
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