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Find the principle and general solutions of `sin x =-sqrt3/2`

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We have .sin x=-(sqrt(3))/(2)=-sin (pi)/(3)=sin (pi+(pi)/(3))=sin (4 pi)/(3).
Hence .sin x=sin (4 pi)/(3)., which gives
.(x)=(n) pi+(-1)^((n)) (4 pi)/(3)., where .(n) in (Z).
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