Express the following in `a+ib` form
`(1/3+3i)^3`

Explanation

((1)/(3)+3i)^(3)=((1)/(3))^(3)+3 xx((1)/(3))^(2) xx 3i+3 xx (1)/(3) xx(3i)^(2)+(3i)^(3).

.=(1)/(27)+(9i)/(9)+1 xx 9 xxi^(2)+27 xx(-(i))=(1)/(27)+(i)-9-27i=(1)/(27) mid-9-26i=(-242)/(27)-26i.