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Evaluate [i^18+(1/i)^25]^3...

Evaluate `[i^18+(1/i)^25]^3`

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[i^(18)+((1)/(i))^(25)]^(3)=[(i^(4))^(4) xx i^(2)+(1)/((i^(4))^(6) i)]^(3)=[1 xx i^(2)+(1)/(1 xx i)]=[-1+(1)/(i)]^(3)=((-i+1)^(3))/(i^(3)).
.=((-i)^(3)+3 xx(-i)^(2) xx 1+3 xx(-i) xx 1^(2)+1^(3))/(-i)=(-1 xx-i+-3-mid 3 hat(i)+1)/(-i)=(-2 i-2)/(-i)=2+(2)/(i).
.=2+(2 i)/(-1)=2-2 i i .
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