Solve the following equations `3x^2-4x+20/3=0`

Explanation

3 x^(2)-4 x+(20)/(3)=0.

.b^(2)-4 a c=(-4)^(2)-4 xx 3 xx (20)/(3)=1 6-80=-64.

The solutions are given by .x=(-b pm sqrt(b^(2)-4 a c))/(2 a)=(-(-4) pm sqrt(-64))/(2 xx 3)=(4 pm 8 i)/(6)=(2 pm 4 i)/(3)=(2)/(3) pm (4)/(3) ,.