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Solve 27 x^(2)-10 x+1=0...

Solve `27 x^(2)-10 x+1=0`

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27 x^(2)-10 x+1=0.
.b^(2)-4 a c=(-10)^(2)-4 xx 27 xx 1=100-108=-8.
.therefore. The solutions are given by .x=(10 pm sqrt(-8))/(2 xx 27)=(10 pm sqrt(8) i)/(2 xx 27)=1 (5 pm sqrt(2)i)/(27)=(5)/(27) pm (sqrt(2))/(27)i.
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