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Evaluate (n !)/((r )!(n-r) !), when n=5,...

Evaluate `(n !)/((r )!(n-r) !)`, when `n=5, r =2`

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We have to evaluate `5 !/2 !(5-2) !` (since `n=5, r=2` ) We have `5 !/2 !(5-2) !=5 !/2 ! xx 3 !=4 xx 5/2=10`
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