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Find the number of permutation of the le...

Find the number of permutation of the letters of the word ALLAHABAD.

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Here, there are 9 objects (letters) of which there are 4A.s, 2L.s and rest are all different.
Therefore, the required number of arrangements `=9 !/4 ! 2 !=5 xx 6 xx 7 xx 8 xx 9/2=7560`
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V PUBLICATION-PERMUTATIONS AND COMBINATIONS-QUESTIONBANK
  1. if 1/(6!) +1/(7!) = x/(8!) , find x.

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  2. Evaluate (n!)/((n-r)!) n = 9, r = 5

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  3. Find the number of permutation of the letters of the word ALLAHABAD.

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  7. Find r , if 5 xx ^4Pr = 6 xx ^5P(r-1)

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  12. How many 4-digit numbers are there with no digit repeated?

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