If `^nC_9 =^nC_8` find 'n' and `^nC_17`

Explanation

We have ` overset(n) dotC_9= overset(n) C_8`

i.e., `n !/9 !(n-9) !=n !/(n-8) ! 8 !`

ôr `1/9=1/n-8` or `n-8=9` or `n=17`

Therefore ` overset(n) C_17=1`