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In the figure, angle A B C=angle A D C a...

In the figure, `angle A B C=angle A D C` and `A B=A D`. Prove that `Delta B C D` is an isosceles triangle.

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Ans: If AB=AD , then angle ABD=angle ADB . angle A dotB C=angle A D C angle A B D+angle C B D=angle A D B+angle C D B angle A B D+angle C B D=angle A B D+angle C D B angle CBD=angle CDB Since angle CBD=angle CDB, B^C C stackrelc/= cdot ddotC D Therefore, Delta BCD is an isoscêles triangle.
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