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If the angles of a hexagon are (x-10)^(c...

If the angles of a hexagon are `(x-10)^(circ)`, `x^0,(x+10)^(circ),(x+20)^(circ),(x+30)^(circ),(x+40)^(circ)`, find the value of `x`.

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Sum of the inner angles of a hexagon `=(6-2) xx 180^(circ)=720^(circ)` `x-10+x+x+10+x+20+x+30+` `x+40=720` `6 x=630` `therefore x=105^(circ)`
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