`int_(-pi/2)^(pi/2)(a cos^(2)x+b sin^(2)x)dx`

int_(-pi/2)^(pi/2) sin^(2) x dx

Evaluate :int_(0)^( pi/2)(a^(2)cos^(2)x+b^(2)sin^(2)x)dx

If A = int_(0)^((pi)/(2))(sin^(3)x)/(1+cos^(2)s)dx and B=int_(0)^((pi)/(2))(cos^(2)x)/(1+sin^(2)x)dx , then (2A)/(B) is equal to

int_(-pi//2)^(pi//2) sin^(2)x cos^(2) x(sin xcos x)dx=

int_(-pi//2)^(pi//2)(sin^(2)x.cos^(2)x(sin x+cos x))dx=

Evaluate: int_(0)^( pi)(pi-x)/(cos^(2)x+b^(2)sin^(2)x)dx

int_(-pi)^(pi)sin^(2)x.cos^(2)x dx=