In the distance between `Na^(+)` and `CI^(-)` ions in sodium chliride crystal is X pm , the length of the edge of the unit cell is

If the distance between Na^+ and Cl^- ions of sodium chloride crystal is 'x' pm, then length of the edge of the unit cell is

If the distance between Na^+ and Cl^(-) ions in NaCl crystal is 'a' pm, the edge length of the unit cell is

If the distance between Na^(+) and Cl^(-) ions in NaCl crystals is 265 pm, then edge length of the unit cell will be ?

The distance between Na^(+) and CI^(-) ion ion NaCI is 281 pm. What is the edge length of the cube

Assertion. The sum of the radii of Na^(+) and Cl^(-) ions in NaCl cystal is 281 pm Hence, edge of the unit cell is 281 pm. Reason. Edge of the unit cell is the distance between the centres of Na^(+) and Cl^(-) ions touching each other.