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Monochromatic light rays parallel to x-a...

Monochromatic light rays parallel to x-axis strike a convex lens AB of refractive index `0.5`. If the lens oscillates such that AB tilts upto a small angle `theta` (in radian) on either side of y-axis, then find the distance between extreme positions of oscillating image:

A

`2f(sectheta-1)`

B

`fsec^(2)theta`

C

`f(sectheta-1)`

D

the image will not move

Text Solution

Verified by Experts


When the lens is tited by `theta`, the image is formed at the intersection (Q) of focal plane of lens in tited position and x-axis.
As the lens ocillates. The image shifts on x-axis in between P and Q
`therefore` Distance between two exterme position of the image `=PQ=(f)/(costheta)-f=f(sectheta-1)`
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