A planet revolves around the sun in elliptical orbit of semimajor axis `2 × 10^(12 )`m. The areal velocity of the planet when it is nearest to the sun is `4.4 × 10^(16) m^(2)/ /s`. The least distance between planet and the sun is `1.8 × 10^(12)` m. Find the minimum speed of the planet in km/s.

Explanation

To find the minimum speed of the planet when it is nearest to the sun, we can use the concept of areal velocity and the properties of elliptical orbits.

### Step-by-Step Solution:

1. **Understanding the Problem**:
- We have a planet revolving around the sun in an elliptical orbit.
- The semi-major axis \( a = 2 \times 10^{12} \, \text{m} \).
- The areal velocity \( A = 4.4 \times 10^{16} \, \text{m}^2/\text{s} \).
...