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A smooth wedge of mass M is pulled towar...

A smooth wedge of mass M is pulled towards left with an acceleration `a= g cot theta` on a horizontal surface and a block of mass m is released w.r.t. wedge. Then answer the following

Time taken by the block to reach the ground is

A

`Mg`

B

`(M+m) g cot theta`

C

`mg sin^(2) theta+Mg`

D

`(M+m)g`

Text Solution

Verified by Experts

The correct Answer is:
A

`N+F_(s) sintheta=mg costheta`
`rArrN=O`
so w.r.t ground block will fall freely.
`h=(1)/(2)g t^(2)` and `h=lsintheta`
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